What is the minimum load demand calculation in kW for a range rated at 6kW and a cooktop rated at 2kW?

Prepare for the Florida Unlimited Electrical Exam. Utilize flashcards and multiple choice questions with hints and detailed explanations to pass confidently!

To determine the minimum load demand calculation for a range rated at 6 kW and a cooktop rated at 2 kW, it's important to apply the demand factors as specified in the NEC (National Electrical Code) guidelines for kitchen appliances.

When calculating the demand for multiple cooking appliances, the NEC allows a reduction in demand for larger appliances. The first 12 kW of cooking demand is calculated at 100%, but for a range rated at 6 kW, this is fully counted. However, since the cooktop is also another appliance, only a portion of its demand is considered.

Typically, when two cooking appliances are present, the 1st appliance, which is larger, is counted wholly (in this case, 6 kW) and the next appliance (the cooktop at 2 kW) is covered at a demand factor, which often allows for a reduction, typically around 30% for the second appliance.

Calculating the demand for the cooktop gives us:

2 kW x 0.30 = 0.6 kW.

Add this to the full demand of the range:

6 kW + 0.6 kW = 6.6 kW.

However

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy